Oregon Who's Good At Math and/or Grammer?

Discussion in 'Pacific Regional Discussion' started by crashdown, Jul 14, 2004.

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  1. crashdown Force Ghost

    Member Since:
    Nov 6, 2003
    star 4
    On a different SW board, I've been challenged in guessing some ones age. They gave me a clue, as follows:

    What you get when a dozen is added to a decade, starved in half, fed by three score more and one that is half a gross, digested down by half a century and half of half a dozen.

    Can anyone in Oregon help me?

    What s a score anyway (is it 20?).
    I think a gross = 144 = twelve dozen

    Cheers to all.

    P.S. This may also be a Grammer question.
  2. _Vengeance_ Jedi Master

    Member Since:
    Jul 1, 2002
    star 4
    Well, you're right that a score is 20, and a gross is twelve dozens (id est, 144.) So, let's take a primary logical look at this question:

    What you get when a dozen is added to a decade, starved in half, fed by three score more and one that is half a gross, digested down by half a century and half of half a dozen.

    What you get when 12 is added to 10, divided by two, multiplied by 132, and divided by 53.

    ([{12+10}/2]x[{20x3}+{144/2}])/([100/2]+[{12/2}/2])

    This would give you 27.396226415


    So try guessing 27, see if you're right. If not, well then, keep cracking at the riddle until you find the right combination of word to mathematical process.

    Hope this helps :)


    Cheers,
    -Derycke
  3. AramysStrael Force Ghost

    Member Since:
    Mar 9, 2004
    star 4
    What you get when a dozen is added to a decade, starved in half, fed by three score more and one that is half a gross, digested down by half a century and half of half a dozen.

    What you get when 12 is added to 10, divided by two, multiplied by 132, and divided by 53.

    ([{12+10}/2]x[{20x3}+{144/2}])/([100/2]+[{12/2}/2])

    This would give you 27.396226415



    I got a different answer, here is how I worked it out:

    ([{12+10}/2]+[{20x3}+{144/2}])/([100/2]+[{12/2}/2])

    = 22 / 2 + 60 + 72 / 50 + 3
    = 11 + 60 + 72 / 53
    = 71 + 72 / 53
    = 143 / 53
    = 2.6981132075471698113207547169811

    I come up with this number because I believe "fed by three score" is adding 20 x 3, not multiplying 11 x 20x3... and so on.

    Granted it has been something like 11 years since I was in any kind of math class, so I could be way off.
    But even if it is supposed to be multiplied, I still get a different answer:

    = 22 / 2 x 60 + 72 / 50 + 3
    = 11 x 132 / 53
    = 1452 / 53
    = 17.64... of course this was plugging the full equation (22/2x60+72/50+3)

    But if you run 1452 / 53, you do get: 27.396226415094339622641509433962


    In conclusion I would like to say I have no clue... thank you!

  4. crashdown Force Ghost

    Member Since:
    Nov 6, 2003
    star 4
    Thanks for your help guys.

    I also got 27.

    I initially got 2.69 also, but it is not correct.
    You accidentally did this [{12+10}/2] x [{20x3}] + [{144/2}]
    instead of this [{12+10}/2] x [{20x3}+{144/2}]

    Oh well, I?ve recently discovered that is does not matter anyway. The clue itself was in error (It?s Not My Fault !!). When I gave the answer as 27 the author of the clue reviewed his clue and discovered that it was written incorrectly.

    The actual clue is as follows:

    What you get when a dozen is added to a decade, starved in half, fed by three score more and one that is half a gross, digested down by half a century and grown from a dozen quartered.

    Well, I set it up this way

    [([{12+10}/2]+[{20x3}+{144/2}])/{100/2}]x{12/4}

    and got 8.58 as my answer, which is also apparently not correct since the author said that 27 was to low.

    Am I still setting this up wrong or is the clue still in error?

    HELP !!!
  5. _Vengeance_ Jedi Master

    Member Since:
    Jul 1, 2002
    star 4
    Alright, through more weird reasoning, I came up with 32. Try that. If it's right, nifty. I'll explain it if it is right, otherwise I'd rather not waste the keystrokes :p

    Cheers,
    -Derycke
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